x^2+4x-5=-2x^2-5x+5

Solution for x^2+4x-5=-2x^2-5x+5 equation:

x^2+4x-5=-2x^2-5x+5

We move all terms to the left:

x^2+4x-5-(-2x^2-5x+5)=0

We get rid of parentheses

x^2+2x^2+5x+4x-5-5=0

We add all the numbers together, and all the variables

3x^2+9x-10=0

a = 3; b = 9; c = -10;
Δ = b2-4ac
Δ = 92-4·3·(-10)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{201}}{2*3}=\frac{-9-\sqrt{201}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{201}}{2*3}=\frac{-9+\sqrt{201}}{6}
$